Title

- title: Unit 3 Sections 5-7 Classwork
- toc: true
- comments: true
- categories: [week 13]

# = ; (idk what this does so I just commented it)

sibnum = int(input('How many siblings do you have?'))
if (sibnum > 3): 
    print("Wow, that is a lot"); 
else: 
    print("That is not very many"); 

gpa = int(input('What is your SAT score?'))
if (gpa > 1051): 
    print("Above average"); 
else: 
    print("Below average"); 

name = str(input('What is your first name?'))
if (len(name) >= 9): 
    print("That's long"); 
else:
    print("Not too long"); 

That is not very many
Above average
That's long

Homework/Hacks

our homework we have decided for a decimal number to binary converter. You must use conditional statements within your code and have a input box for where the decimal number will go. This will give you a 2.7 out of 3 and you may add anything else to the code to get above a 2.7.

Below is an example of decimal number to binary converter which you can use as a starting template.

def DecimalToBinary(num):
    strs = ""
    while num:
        # if (num & 1) = 1
        if (num & 1):
            strs += "1"
        # if (num & 1) = 0
        else:
            strs += "0"
        # right shift by 1
        num >>= 1
    return strs
 
# function to reverse the string
def reverse(strs):
    print(strs[::-1])
 
# Driver Code
num = 67
print("Binary of num 67 is:", end=" ")
reverse(DecimalToBinary(num))

Binary of num 67 is: 1000011

Below is my work

def convert(n): 
    if n == 0:
        print("0")
    elif n == 1:
        print("1")
    else:
        binary = "" # define a string "" variable for storing binary digits; calculated below
        # divide the number (n) by 2, until it becomes 0, and store the remainder in the above string variable
        while int(n) > 0:
            binary += str(i]nt(n%2)) # retreive the remainder, and keep appending to the string
            n = n / 2 # change the number to its quotient, then repeat
        print(binary[::-1]) # now the binary string has all the desired digits, but in reverse order
        # :: is how to reverse string
        
n = int(input('Enter a number'))
convert(n) # perform the function

1000

import random

def randomnum(): # function for generating random int
    n = random.randint(0,255)
    print("The random decimal number generated is " + str(n))
    return n

def converttobin(n): 
    if n == 0:
        print("00000000")
        return "00000000"
    elif n == 1:
        print("00000001")
        return "00000001"
    else:
        binary = "" # define a string "" variable for storing binary digits; calculated below
        # divide the number (n) by 2, until it becomes 0, and store the remainder in the above string variable
        while int(n) > 0:
            binary += str(int(n%2)) # retreive the remainder, and keep appending to the string
            n = n / 2 # change the number to its quotient, then repeat
        print(binary[::-1]) # now the binary string has all the desired digits, but in reverse order
        # :: is how to reverse string
        return binary

def survivors(binary):
    survivorstatus = ["Jiya", "Shruthi", "Noor", "Ananya" , "Peter Parker", "Andrew Garfield", "Tom Holland", "Tobey Maguire"]
    idx = 0
    for bit in binary:
        if (bit == "0"):
            print(survivorstatus[idx] + " is a ZOMBIE!!!")
        else:
            print(survivorstatus[idx] + " survived!!!")
        idx += 1 # advancing the index to the next position

survivors(converttobin(randomnum())) # perform all the functions

The random decimal number generated is 120
1111000
Jiya is a ZOMBIE!!!
Shruthi is a ZOMBIE!!!
Noor is a ZOMBIE!!!
Ananya survived!!!
Peter Parker survived!!!
Andrew Garfield survived!!!
Tom Holland survived!!!